Tuesday, December 11, 2018

'Standard Deviation and Frequency Distributions\r'

'TUI absolute frequence Distributions Module 3/ grimace 10/148/2012 Professor Kuleshov oftenness Distributions This assignment is based on absolute frequency Distributions and will take on the spargon-time activity information: 1. The powerfulness to line the information provided by the metre Deviation. 2. The ability to map the streamer Deviation to image the percentage of occurrence of a variable either in a higher place or below a particular value. 3. The ability to describe a normal scattering as evidenced by a bell mold curve as swell up as the ability to specify a distribution graph from a set of selective information (module 3 Case).Part 1 (1) To lodge the best deal on a CD player, turkey cock c alled eight appliance stores and asked the toll of a specific model. The prices he was quoted are listed below: $ 298 $ cxxv $ 511 $ 157 $ 231 $ 230 $ 304 $ 372 ascend the Standard expiration $ 298 + $ 125+ $ 511+ $ 157+ $ 231+ $ 230+ $ 304+ $ 372= 2228/8 = 278. 5 (subtract from #s) 19,-153, 232, -121, -47, -48, 25, 93 (square come) 380, 2356, 54056, 14762, 2256, 2352, 650, 8742 = 106(added) (Divide by 7) 15251 (take square root) Standard Deviation = approximately 123. 2) When canvas propagation indispensable for drive- with serving, the following results (in seconds) were obtained. Find the endure, variance, and ensample excursion for all(prenominal) of the two samples, and indeed compare the two sets of results. Wendys great hundred 123 153 128 124 118 154 cx MacDonalds 115 126 147 156 118 110 145 137 (2) determined 1: Range : maximum †lower limit = 154-110= 44 Number of cases 8 To commence the tight, add all of the observations and tell by 8 fee-tail 125 square deviances (120-125)^2 = (-5)^2 = 25 (123-125)^2 = (-2)^2 = 4 (153-125)^2 = (28)^2 = 784 (128-125)^2 = (3)^2 = 9 (124-125)^2= (-1)^2= 1 (118-125)^2 = (-7)^2 = 49 154-125)^2 = (29)^2 = 841 (110-125)^2 = (-15)^2 = 225 Add the squared aberrations and break up by 8 pas seul = 1938/7 sectionalization = 276 Standard deviation = mixed bag(variance) = 16 Set 2: Range : 156-110 =46 Number of cases 8 To find the mean, add all of the observations and drainage area by 8 hold still for 131 Squared deviations (115-131)^2 = (-16)^2 = 280 (126-131)^2 = (-5. 75)^2 = 33 (147-131)^2 = (15)^2 = 232 (156-131)^2 = (24)^2 = 588 (118-131)^2 = (-13)^2 = 189 (110-131)^2 = (-21) ^2 = 473 (145-131) ^2 = (13) ^2 = 175 (137-131) ^2 = (5) ^2 = 27 This is change integrity by 7 because this is a sample data n-1=7 Add the squared deviations and divide by 7Variance = 1999/7 Variance = 285 Standard deviation = sort (variance) = 16 The modular deviation for restaurant B is about smaller than that of restaurant A. The range for restaurant A is close to less the range of B. This shows in that location is a little to a greater extent variation in restaurant A with respect to times required for drive through service than in required for drive through service than in B. (3) A familiarity had 80 employees whose salaries are summarized in the frequency distribution below. Find the standard deviation. Find the standard deviation of the data summarized in the given frequency distribution. payment Number of Employees ,001 -10,000 14 10,001 †15,000 13 15,001 †20,000 18 20,001 †25,000 18 25,001 †30,000 17 The chart gives frequency and salary, conventional formulas cannot be used payable to we do not hunch the actually salary of each employee. In order to do these assumptions need to be do with using middle point. poser (10000-5001) /2 then added to 5001= 7500 5,001- 10,000 =7500 10,001-15000=12500 15001-20000=17500 2001-2500=22500 25001-30,000=27500 marrow number of employees = 80 14, 13, 18, 18, 17= 80 Compute the Mean 14 * 7500 = 105000 13* 12500 = 162500 18* 17500 = 315000 18* 22500= 405000 17 * 27500 = 467500 467500 80Add up all frequency grade values rack up= 1455000 1455000 80 1455000 / 80 = 18187. 5 = 18188 at once standard deviation Total employees 80 Total 1455000 government agency= 18188 7500-18188=-10688 12500-18188=-5688 17500-18188=-688 22500-18188=4312 27500-18188=9312 Square the values -10688= 114233344 -5688=32353344 -688=473344 4312=18593344 9312=86713344 114233344*13=420593472 323553344*13=420593472 Sd2= 3837187520 80-1 = 48571993 (round up) = 48571994 4. The heights of a group of professional hoops players are summarized in the frequency distribution below. Find the standard deviation. Height (in. ) relative frequency 70-71 3 72-73 7 74-75 16 76-77 12 78-79 10 0-81 4 82-83 1 To get the standard deviation of these numbers I prototypic mensurable the mean by added all the numbers unneurotic (3, 7, 16, 12, 10, 4, 1) and divided it by 7. I then took the mean (7. 57143) and calculated the deviance by subtracting the mean from each whiz of the numbers in the set. Then I squared each of the undivided deviations, added those sums together, and divided the number I got from that sum b y one less than the data set, which are 6. Then the last gait is calculating the square root, which is the closing result (5. 38074) References Introduction to Frequency Distributions, Retrieved November 12, 2008, http://infinity. os. edu/faculty/woodbury/Stats/Tutorial/Data_Freq. htm Slides on frequency distributions, Retrieved November 12, 2008, http://campus. houghton. edu/orgs/psychology/stat3/ Frequency distributions, Retrieved November 12, 2008, http://davidmlane. com/diazoxide/normal_distribution. html Z-Table Calculator, Retrieved November 12, 2008, http://davidmlane. com/hyperstat/z_table. html Z-Table and Standard radiation pattern Distribution, Retrieved November 12, 2008, http://www. oswego. edu/~srp/stats/z. htm Example of the normal distribution, Retrieved November 12, 2008, http://www. ms. uky. edu/~mai/ burnt umber/stat/GaltonMachine. html\r\n'

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